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What is the magnitude of the vector (2, -3, 6)?
What is the magnitude of the vector (2, -3, 6)?
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Practice Questions
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Q1
What is the magnitude of the vector (2, -3, 6)?
7
9
8
5
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Magnitude = √(2^2 + (-3)^2 + 6^2) = √(4 + 9 + 36) = √49 = 7.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the magnitude of the vector (2, -3, 6)?
Solution:
Magnitude = √(2^2 + (-3)^2 + 6^2) = √(4 + 9 + 36) = √49 = 7.
Steps: 9
Show Steps
Step 1: Identify the components of the vector. The vector is (2, -3, 6), which has three components: 2, -3, and 6.
Step 2: Square each component of the vector. Calculate 2^2, (-3)^2, and 6^2.
Step 3: Calculate 2^2 = 4.
Step 4: Calculate (-3)^2 = 9.
Step 5: Calculate 6^2 = 36.
Step 6: Add the squared values together. So, add 4 + 9 + 36.
Step 7: Calculate the sum: 4 + 9 = 13, and then 13 + 36 = 49.
Step 8: Take the square root of the sum. Calculate √49.
Step 9: Find the square root of 49, which is 7.
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