Solve the equation 2sin(x) + √3 = 0 for x in the interval [0, 2π].

Practice Questions

Q1
Solve the equation 2sin(x) + √3 = 0 for x in the interval [0, 2π].
  1. 5π/3
  2. π/3
  3. 2π/3
  4. 4π/3

Questions & Step-by-Step Solutions

Solve the equation 2sin(x) + √3 = 0 for x in the interval [0, 2π].
Correct Answer: 4π/3, 5π/3
  • Step 1: Start with the equation 2sin(x) + √3 = 0.
  • Step 2: Subtract √3 from both sides to isolate the term with sin(x): 2sin(x) = -√3.
  • Step 3: Divide both sides by 2 to solve for sin(x): sin(x) = -√3/2.
  • Step 4: Identify the angles where sin(x) equals -√3/2. These angles are in the third and fourth quadrants.
  • Step 5: The angles that satisfy sin(x) = -√3/2 are x = 4π/3 and x = 5π/3.
  • Step 6: Write the final solutions: x = 4π/3 and x = 5π/3.
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