Solve the equation 2sin(x) + √3 = 0 for x in the interval [0, 2π].

Practice Questions

1 question
Q1
Solve the equation 2sin(x) + √3 = 0 for x in the interval [0, 2π].
  1. 5π/3
  2. π/3
  3. 2π/3
  4. 4π/3

Questions & Step-by-step Solutions

1 item
Q
Q: Solve the equation 2sin(x) + √3 = 0 for x in the interval [0, 2π].
Solution: Rearranging gives sin(x) = -√3/2, so x = 4π/3 and x = 5π/3.
Steps: 6

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