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If sin(θ) = 0, what are the possible values of θ in the interval [0, 2π]?
If sin(θ) = 0, what are the possible values of θ in the interval [0, 2π]?
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Practice Questions
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Q1
If sin(θ) = 0, what are the possible values of θ in the interval [0, 2π]?
0, π
0, 2π
π/2, 3π/2
π/4, 3π/4
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The angles where sin(θ) = 0 in the interval [0, 2π] are θ = 0 and θ = π.
Questions & Step-by-step Solutions
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Q
Q: If sin(θ) = 0, what are the possible values of θ in the interval [0, 2π]?
Solution:
The angles where sin(θ) = 0 in the interval [0, 2π] are θ = 0 and θ = π.
Steps: 4
Show Steps
Step 1: Understand that sin(θ) = 0 means we are looking for angles where the sine function equals zero.
Step 2: Recall that the sine function is zero at specific angles on the unit circle.
Step 3: Identify the angles in the interval [0, 2π] where sine is zero. These angles are 0 and π.
Step 4: Conclude that the possible values of θ in the interval [0, 2π] are θ = 0 and θ = π.
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