A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at ran

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Question: A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is not blue?

Options:

Correct Answer: 2/3

Solution:

Total marbles = 4 + 5 + 6 = 15. Non-blue marbles = 4 + 5 = 9. Probability = 9/15 = 3/5.

A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is not blue?

A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is not blue?

Step 1: Count the total number of marbles in the jar. There are 4 red, 5 green, and 6 blue marbles.
Step 2: Add the number of red, green, and blue marbles together: 4 + 5 + 6 = 15. This is the total number of marbles.
Step 3: Count the number of non-blue marbles. Non-blue marbles are red and green, so add them: 4 (red) + 5 (green) = 9.
Step 4: To find the probability of drawing a non-blue marble, divide the number of non-blue marbles by the total number of marbles: 9 (non-blue) / 15 (total) = 9/15.
Step 5: Simplify the fraction 9/15. Both 9 and 15 can be divided by 3, so 9/15 simplifies to 3/5.

Probability – The likelihood of an event occurring, calculated as the ratio of favorable outcomes to total outcomes.
Counting Principles – Understanding how to count total and favorable outcomes in a probability scenario.