A box contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is white given that it is not black?

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Q: A box contains 4 white and 6 black balls. If one ball is drawn at random, what is the probability that it is white given that it is not black?

Solution: If the ball is not black, it must be white. Therefore, P(White | Not Black) = 1.

Steps: 5

Step 1: Understand the problem. We have a box with 4 white balls and 6 black balls.
Step 2: Identify the total number of balls. There are 4 white + 6 black = 10 balls in total.
Step 3: Focus on the condition given in the question. We need to find the probability of drawing a white ball given that the ball drawn is not black.
Step 4: If the ball is not black, it can only be white because there are no other colors.
Step 5: Since the only option left (not black) is white, the probability of drawing a white ball in this case is 1.