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What is the equation of the circle with center (2, -3) and radius 4?
What is the equation of the circle with center (2, -3) and radius 4?
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Practice Questions
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Q1
What is the equation of the circle with center (2, -3) and radius 4?
(x-2)² + (y+3)² = 16
(x+2)² + (y-3)² = 16
(x-2)² + (y-3)² = 16
(x+2)² + (y+3)² = 16
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Equation of circle: (x-h)² + (y-k)² = r² => (x-2)² + (y+3)² = 4² = 16.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equation of the circle with center (2, -3) and radius 4?
Solution:
Equation of circle: (x-h)² + (y-k)² = r² => (x-2)² + (y+3)² = 4² = 16.
Steps: 5
Show Steps
Step 1: Identify the center of the circle. The center is given as (2, -3). Here, h = 2 and k = -3.
Step 2: Identify the radius of the circle. The radius is given as 4.
Step 3: Write the general equation of a circle. The equation is (x - h)² + (y - k)² = r².
Step 4: Substitute the values of h, k, and r into the equation. This gives us (x - 2)² + (y + 3)² = 4².
Step 5: Calculate 4², which is 16. So, the equation becomes (x - 2)² + (y + 3)² = 16.
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