For the function f(x) = x^2 - 2x + 1, find the slope of the tangent line at x =

Practice Questions

Q1
For the function f(x) = x^2 - 2x + 1, find the slope of the tangent line at x = 1.
  1. 0
  2. 1
  3. 2
  4. 3

Questions & Step-by-Step Solutions

For the function f(x) = x^2 - 2x + 1, find the slope of the tangent line at x = 1.
Correct Answer: 0
  • Step 1: Identify the function given, which is f(x) = x^2 - 2x + 1.
  • Step 2: Find the derivative of the function, which represents the slope of the tangent line. The derivative f'(x) is calculated as follows: f'(x) = 2x - 2.
  • Step 3: Substitute x = 1 into the derivative to find the slope at that point. So, calculate f'(1) = 2(1) - 2.
  • Step 4: Simplify the expression: f'(1) = 2 - 2 = 0.
  • Step 5: Conclude that the slope of the tangent line at x = 1 is 0.
  • Derivative – The derivative of a function represents the slope of the tangent line at any given point.
  • Quadratic Functions – Understanding the properties of quadratic functions, including their vertex and slope at specific points.
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