Find the critical points of the function f(x) = x^3 - 6x^2 + 9x.

Practice Questions

Q1
Find the critical points of the function f(x) = x^3 - 6x^2 + 9x.
  1. (0, 0)
  2. (3, 0)
  3. (2, 0)
  4. (1, 0)

Questions & Step-by-Step Solutions

Find the critical points of the function f(x) = x^3 - 6x^2 + 9x.
Correct Answer: (1, 4) and (3, 0)
  • Step 1: Write down the function f(x) = x^3 - 6x^2 + 9x.
  • Step 2: Find the derivative of the function, which is f'(x). The derivative of f(x) is f'(x) = 3x^2 - 12x + 9.
  • Step 3: Set the derivative equal to zero to find critical points: 3x^2 - 12x + 9 = 0.
  • Step 4: Simplify the equation by dividing everything by 3: x^2 - 4x + 3 = 0.
  • Step 5: Factor the quadratic equation: (x - 1)(x - 3) = 0.
  • Step 6: Solve for x by setting each factor to zero: x - 1 = 0 gives x = 1, and x - 3 = 0 gives x = 3.
  • Step 7: Now, find the y-values for the critical points by substituting x back into the original function f(x).
  • Step 8: Calculate f(1) = 1^3 - 6(1^2) + 9(1) = 1 - 6 + 9 = 4, so the first critical point is (1, 4).
  • Step 9: Calculate f(3) = 3^3 - 6(3^2) + 9(3) = 27 - 54 + 27 = 0, so the second critical point is (3, 0).
  • Step 10: The critical points are (1, 4) and (3, 0).
  • Finding Critical Points – This involves taking the derivative of a function, setting it to zero, and solving for x to find points where the function's slope is zero.
  • Evaluating Function at Critical Points – After finding the critical points, it is important to evaluate the original function at these points to determine their coordinates.
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