What is the molarity of a solution if 10 g of glucose (C6H12O6) is dissolved in

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Question: What is the molarity of a solution if 10 g of glucose (C6H12O6) is dissolved in 250 mL of water? (Molar mass = 180 g/mol)

Options:

Correct Answer: 0.22 M

Solution:

Moles of glucose = 10 g / 180 g/mol = 0.0556 moles. Molarity = 0.0556 moles / 0.25 L = 0.222 M.

What is the molarity of a solution if 10 g of glucose (C6H12O6) is dissolved in 250 mL of water? (Molar mass = 180 g/mol)

What is the molarity of a solution if 10 g of glucose (C6H12O6) is dissolved in 250 mL of water? (Molar mass = 180 g/mol)

Step 1: Find the molar mass of glucose (C6H12O6), which is given as 180 g/mol.
Step 2: Calculate the number of moles of glucose by dividing the mass of glucose (10 g) by its molar mass (180 g/mol).
Step 3: Use the formula: Moles of glucose = 10 g / 180 g/mol = 0.0556 moles.
Step 4: Convert the volume of the solution from milliliters to liters. Since 250 mL = 0.25 L.
Step 5: Calculate the molarity using the formula: Molarity = Moles of solute / Volume of solution in liters.
Step 6: Substitute the values: Molarity = 0.0556 moles / 0.25 L = 0.222 M.

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