Which of the following species is reduced in the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O?
Practice Questions
1 question
Q1
Which of the following species is reduced in the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O?
MnO4-
C2O4^2-
H+
CO2
In the given reaction, MnO4- is reduced to Mn^2+.
Questions & Step-by-step Solutions
1 item
Q
Q: Which of the following species is reduced in the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O?
Solution: In the given reaction, MnO4- is reduced to Mn^2+.
Steps: 4
Step 1: Identify the reactants and products in the reaction: 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O.
Step 2: Determine the oxidation states of manganese (Mn) in MnO4- and Mn^2+. In MnO4-, Mn has an oxidation state of +7, and in Mn^2+, Mn has an oxidation state of +2.
Step 3: Compare the oxidation states. Since the oxidation state of Mn decreases from +7 in MnO4- to +2 in Mn^2+, this means MnO4- is gaining electrons.
Step 4: Conclude that the species that is reduced is the one that gains electrons. Therefore, MnO4- is reduced to Mn^2+.
