Question: Which of the following species is reduced in the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O?
Options:
MnO4-
C2O4^2-
H+
CO2
Correct Answer: MnO4-
Solution:
In the given reaction, MnO4- is reduced to Mn^2+.
Which of the following species is reduced in the reaction 2MnO4- + 5C2O4^2- + 16
Practice Questions
Q1
Which of the following species is reduced in the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O?
MnO4-
C2O4^2-
H+
CO2
Questions & Step-by-Step Solutions
Which of the following species is reduced in the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O?
Correct Answer: MnO4-
Step 1: Identify the reactants and products in the reaction: 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O.
Step 2: Determine the oxidation states of manganese (Mn) in MnO4- and Mn^2+. In MnO4-, Mn has an oxidation state of +7, and in Mn^2+, Mn has an oxidation state of +2.
Step 3: Compare the oxidation states. Since the oxidation state of Mn decreases from +7 in MnO4- to +2 in Mn^2+, this means MnO4- is gaining electrons.
Step 4: Conclude that the species that is reduced is the one that gains electrons. Therefore, MnO4- is reduced to Mn^2+.
No concepts available.
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