How many grams of KCl are needed to prepare 0.5 moles of KCl?

How many grams of KCl are needed to prepare 0.5 moles of KCl?

Correct Answer: 37.25 g

Step 1: Find the molar mass of KCl. KCl is made of potassium (K) and chlorine (Cl). The atomic mass of K is approximately 39.1 g/mol and Cl is approximately 35.5 g/mol.
Step 2: Add the atomic masses together to get the molar mass of KCl. So, 39.1 g/mol + 35.5 g/mol = 74.6 g/mol (rounded to 74.5 g/mol).
Step 3: Determine how many moles of KCl you want to prepare. In this case, it is 0.5 moles.
Step 4: Use the formula: mass (in grams) = number of moles x molar mass. Here, it will be 0.5 moles x 74.5 g/mol.
Step 5: Calculate the mass. 0.5 x 74.5 = 37.25 grams.
Step 6: Conclude that you need 37.25 grams of KCl to prepare 0.5 moles.

Molar Mass Calculation – Understanding how to calculate the mass of a substance using its molar mass and the number of moles.
Stoichiometry – Applying stoichiometric principles to convert between moles and grams.