Find the odd one out in the series: 7, 14, 21, 28, 35, 42, 50.

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Question: Find the odd one out in the series: 7, 14, 21, 28, 35, 42, 50.

Options:

Correct Answer: 50

Solution:

All numbers except 50 are multiples of 7. 50 is the odd one out.

Find the odd one out in the series: 7, 14, 21, 28, 35, 42, 50.

Find the odd one out in the series: 7, 14, 21, 28, 35, 42, 50.

Step 1: Look at the series of numbers: 7, 14, 21, 28, 35, 42, 50.
Step 2: Identify what the numbers have in common. Check if they are multiples of a certain number.
Step 3: Start with the first number, 7. Check if the other numbers can be divided by 7 without a remainder.
Step 4: Divide each number by 7: 7 ÷ 7 = 1, 14 ÷ 7 = 2, 21 ÷ 7 = 3, 28 ÷ 7 = 4, 35 ÷ 7 = 5, 42 ÷ 7 = 6.
Step 5: Notice that all these results are whole numbers (1, 2, 3, 4, 5, 6). This means they are all multiples of 7.
Step 6: Now check the last number, 50. Divide 50 by 7: 50 ÷ 7 = 7.14, which is not a whole number.
Step 7: Since 50 cannot be divided by 7 evenly, it is not a multiple of 7.
Step 8: Conclude that 50 is the odd one out because it is not a multiple of 7, while all the other numbers are.

Multiples of 7 – The series consists of numbers that are multiples of 7, except for the number 50.