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If a mixture of two liquids A and B is in the ratio 3:5 and the total volume is

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Question: If a mixture of two liquids A and B is in the ratio 3:5 and the total volume is 80 liters, how many liters of liquid A are in the mixture?

Options:

  1. 30 liters
  2. 40 liters
  3. 50 liters
  4. 60 liters

Correct Answer: 30 liters

Solution: 

Let the volumes of A and B be 3x and 5x respectively. Then, 3x + 5x = 80 liters, 8x = 80, x = 10. Therefore, volume of A = 3x = 30 liters.

If a mixture of two liquids A and B is in the ratio 3:5 and the total volume is

Practice Questions

Q1
If a mixture of two liquids A and B is in the ratio 3:5 and the total volume is 80 liters, how many liters of liquid A are in the mixture?
  1. 30 liters
  2. 40 liters
  3. 50 liters
  4. 60 liters

Questions & Step-by-Step Solutions

If a mixture of two liquids A and B is in the ratio 3:5 and the total volume is 80 liters, how many liters of liquid A are in the mixture?
  • Step 1: Understand the ratio of liquids A and B, which is 3:5.
  • Step 2: This means for every 3 parts of liquid A, there are 5 parts of liquid B.
  • Step 3: Let 'x' be a common multiplier for the parts. So, the volume of liquid A is 3x and the volume of liquid B is 5x.
  • Step 4: Add the volumes of A and B together: 3x + 5x = 8x.
  • Step 5: We know the total volume of the mixture is 80 liters, so set up the equation: 8x = 80.
  • Step 6: Solve for x by dividing both sides of the equation by 8: x = 80 / 8 = 10.
  • Step 7: Now, find the volume of liquid A by substituting x back into the equation for A: Volume of A = 3x = 3 * 10 = 30 liters.
  • Ratios and Proportions – Understanding how to express quantities in a given ratio and solve for unknowns using algebra.
  • Algebraic Equations – Setting up and solving linear equations based on the information provided in the problem.
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