A mixture of two liquids A and B is in the ratio 4:1. If 50 liters of the mixtur

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Question: A mixture of two liquids A and B is in the ratio 4:1. If 50 liters of the mixture is prepared, how much liquid B is there?

Options:

Correct Answer: 10 liters

Solution:

Total parts = 4 + 1 = 5. Liquid B = (1/5) * 50 = 10 liters.

A mixture of two liquids A and B is in the ratio 4:1. If 50 liters of the mixture is prepared, how much liquid B is there?

A mixture of two liquids A and B is in the ratio 4:1. If 50 liters of the mixture is prepared, how much liquid B is there?

Step 1: Understand the ratio of liquids A and B, which is 4:1. This means for every 4 parts of liquid A, there is 1 part of liquid B.
Step 2: Add the parts of the ratio together. 4 (for A) + 1 (for B) = 5 total parts.
Step 3: Determine how much one part is worth. Since the total mixture is 50 liters, divide 50 by the total parts: 50 liters / 5 parts = 10 liters per part.
Step 4: Find out how much liquid B is in the mixture. Since liquid B is 1 part, it is equal to 10 liters.

Ratio and Proportion – Understanding how to divide quantities based on given ratios.
Mixture Problems – Calculating the amounts of components in a mixture based on their ratio.