If a man is 45 years old now, how many years ago was he twice as old as his son

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Question: If a man is 45 years old now, how many years ago was he twice as old as his son who is currently 15 years old?

Options:

Correct Answer: 15

Solution:

Let x years ago, the man\'s age was 45 - x and the son\'s age was 15 - x. We have 45 - x = 2(15 - x). Solving gives x = 15.

If a man is 45 years old now, how many years ago was he twice as old as his son who is currently 15 years old?

If a man is 45 years old now, how many years ago was he twice as old as his son who is currently 15 years old?

Step 1: Identify the current ages of the man and his son. The man is 45 years old and the son is 15 years old.
Step 2: Define 'x' as the number of years ago we want to find.
Step 3: Write the man's age 'x' years ago: 45 - x.
Step 4: Write the son's age 'x' years ago: 15 - x.
Step 5: Set up the equation based on the condition that the man was twice as old as his son 'x' years ago: 45 - x = 2(15 - x).
Step 6: Simplify the equation: 45 - x = 30 - 2x.
Step 7: Rearrange the equation to isolate 'x': 45 - 30 = -2x + x.
Step 8: Combine like terms: 15 = -x.
Step 9: Solve for 'x': x = 15.
Step 10: Conclude that 15 years ago, the man was twice as old as his son.

Age Problem Solving – This question tests the ability to set up and solve equations based on relationships between ages over time.
Algebraic Manipulation – It requires the application of algebra to isolate variables and solve for unknowns.