If a mixture of 60% alcohol and 40% water is diluted with 20 liters of water, wh

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Question: If a mixture of 60% alcohol and 40% water is diluted with 20 liters of water, what is the new percentage of alcohol in the mixture?

Options:

Correct Answer: 50%

Solution:

Let the initial volume be 100 liters. Alcohol = 60 liters. New volume = 100 + 20 = 120 liters. New percentage = (60/120) * 100 = 50%.

If a mixture of 60% alcohol and 40% water is diluted with 20 liters of water, what is the new percentage of alcohol in the mixture?

If a mixture of 60% alcohol and 40% water is diluted with 20 liters of water, what is the new percentage of alcohol in the mixture?

Step 1: Assume the initial volume of the mixture is 100 liters.
Step 2: Calculate the amount of alcohol in the mixture. Since it is 60% alcohol, the amount of alcohol is 60 liters.
Step 3: Add 20 liters of water to the mixture. This means the new total volume of the mixture is 100 liters + 20 liters = 120 liters.
Step 4: Calculate the new percentage of alcohol in the mixture. Use the formula: (amount of alcohol / new total volume) * 100.
Step 5: Substitute the values: (60 liters / 120 liters) * 100 = 50%.
Step 6: The new percentage of alcohol in the mixture is 50%.

Mixture and Dilution – Understanding how to calculate the concentration of a solution after adding more solvent.
Percentage Calculation – Calculating the new percentage of a component in a mixture after dilution.