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A mixture contains 30% alcohol and 70% water. If 20 liters of the mixture is tak

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Question: A mixture contains 30% alcohol and 70% water. If 20 liters of the mixture is taken out, how much alcohol is left in the mixture?

Options:

  1. 6 liters
  2. 14 liters
  3. 8 liters
  4. 12 liters

Correct Answer: 12 liters

Solution:

Initially, the mixture has 30% alcohol. In 20 liters, alcohol = 30% of 20 = 6 liters. Remaining alcohol = Initial alcohol - Alcohol taken out. If the total mixture is 100 liters, initial alcohol = 30 liters. Remaining alcohol = 30 - 6 = 24 liters.

A mixture contains 30% alcohol and 70% water. If 20 liters of the mixture is tak

Practice Questions

Q1
A mixture contains 30% alcohol and 70% water. If 20 liters of the mixture is taken out, how much alcohol is left in the mixture?
  1. 6 liters
  2. 14 liters
  3. 8 liters
  4. 12 liters

Questions & Step-by-Step Solutions

A mixture contains 30% alcohol and 70% water. If 20 liters of the mixture is taken out, how much alcohol is left in the mixture?
  • Step 1: Understand that the mixture is made up of 30% alcohol and 70% water.
  • Step 2: Determine the total amount of the mixture. In this case, we assume the total mixture is 100 liters for easy calculation.
  • Step 3: Calculate the initial amount of alcohol in the mixture. Since it is 30% alcohol, the initial alcohol = 30% of 100 liters = 30 liters.
  • Step 4: Calculate how much alcohol is in the 20 liters of mixture that is taken out. Alcohol in 20 liters = 30% of 20 liters = 6 liters.
  • Step 5: Subtract the amount of alcohol taken out from the initial amount of alcohol. Remaining alcohol = Initial alcohol - Alcohol taken out = 30 liters - 6 liters = 24 liters.
  • Percentage Calculation – Understanding how to calculate a percentage of a quantity and apply it to a mixture.
  • Mixture and Volume – Understanding how to determine the remaining quantity of a component in a mixture after a portion is removed.
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