Question: If a certain pollutant decreases in concentration by 25% each year, what will be the concentration after 2 years if the initial concentration is 160 mg/L?
Options:
Correct Answer: 80 mg/L
Solution:
After 1 year: 160 - 0.25 * 160 = 120 mg/L. After 2 years: 120 - 0.25 * 120 = 90 mg/L.