What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?

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Question: What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?

Options:

Correct Answer: +3

Solution:

Let the oxidation state of Cr be x. The equation is x + 4(0) + 2(-1) = +1. Solving gives x = +3.

What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?

What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?

Step 1: Identify the complex ion [Cr(NH3)4Cl2]+ and note that it has a +1 charge.
Step 2: Assign oxidation states to the components: NH3 (ammonia) has an oxidation state of 0, and Cl (chloride) has an oxidation state of -1.
Step 3: Let the oxidation state of chromium (Cr) be represented as x.
Step 4: Write the equation based on the oxidation states: x + 4(0) + 2(-1) = +1.
Step 5: Simplify the equation: x + 0 - 2 = +1.
Step 6: Rearrange the equation to solve for x: x - 2 = +1.
Step 7: Add 2 to both sides: x = +1 + 2.
Step 8: Calculate the value: x = +3.

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