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What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?

Practice Questions

Q1
What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?
  1. +2
  2. +3
  3. +4
  4. +6

Questions & Step-by-Step Solutions

What is the oxidation state of chromium in [Cr(NH3)4Cl2]+?
  • Step 1: Identify the complex ion [Cr(NH3)4Cl2]+ and note that it has a +1 charge.
  • Step 2: Assign oxidation states to the components: NH3 (ammonia) has an oxidation state of 0, and Cl (chloride) has an oxidation state of -1.
  • Step 3: Let the oxidation state of chromium (Cr) be represented as x.
  • Step 4: Write the equation based on the oxidation states: x + 4(0) + 2(-1) = +1.
  • Step 5: Simplify the equation: x + 0 - 2 = +1.
  • Step 6: Rearrange the equation to solve for x: x - 2 = +1.
  • Step 7: Add 2 to both sides: x = +1 + 2.
  • Step 8: Calculate the value: x = +3.
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