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If a 3 kg object is moving with a speed of 4 m/s and comes to a stop, what is th
If a 3 kg object is moving with a speed of 4 m/s and comes to a stop, what is the work done by friction?
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Q1
If a 3 kg object is moving with a speed of 4 m/s and comes to a stop, what is the work done by friction?
-24 J
-48 J
0 J
24 J
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Initial kinetic energy = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 24 J. Work done by friction = -24 J.
Questions & Step-by-step Solutions
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Q
Q: If a 3 kg object is moving with a speed of 4 m/s and comes to a stop, what is the work done by friction?
Solution:
Initial kinetic energy = 0.5 × m × v² = 0.5 × 3 kg × (4 m/s)² = 24 J. Work done by friction = -24 J.
Steps: 9
Show Steps
Step 1: Identify the mass of the object. The mass (m) is 3 kg.
Step 2: Identify the speed of the object. The speed (v) is 4 m/s.
Step 3: Use the formula for kinetic energy: KE = 0.5 × m × v².
Step 4: Plug in the values: KE = 0.5 × 3 kg × (4 m/s)².
Step 5: Calculate (4 m/s)², which is 16 m²/s².
Step 6: Multiply 0.5 × 3 kg × 16 m²/s² to get 24 J.
Step 7: The initial kinetic energy of the object is 24 J.
Step 8: When the object comes to a stop, all of this energy is used to overcome friction.
Step 9: The work done by friction is equal to the negative of the initial kinetic energy, which is -24 J.
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