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If two chords AB and CD intersect at point E inside a circle, and AE = 3 cm, EB

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Question: If two chords AB and CD intersect at point E inside a circle, and AE = 3 cm, EB = 5 cm, what is the length of CE if ED = 4 cm?

Options:

  1. 6
  2. 8
  3. 12
  4. 10

Correct Answer: 6

Solution: 

Using the intersecting chords theorem: AE * EB = CE * ED, we have 3 * 5 = CE * 4, thus 15 = CE * 4, so CE = 15/4 = 3.75, which rounds to 4.

If two chords AB and CD intersect at point E inside a circle, and AE = 3 cm, EB

Practice Questions

Q1
If two chords AB and CD intersect at point E inside a circle, and AE = 3 cm, EB = 5 cm, what is the length of CE if ED = 4 cm?
  1. 6
  2. 8
  3. 12
  4. 10

Questions & Step-by-Step Solutions

If two chords AB and CD intersect at point E inside a circle, and AE = 3 cm, EB = 5 cm, what is the length of CE if ED = 4 cm?
  • Intersecting Chords Theorem – This theorem states that if two chords intersect inside a circle, the products of the lengths of the segments of each chord are equal.
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