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A 2 kg object is dropped from a height of 5 m. What is the potential energy at t
A 2 kg object is dropped from a height of 5 m. What is the potential energy at the top? (g = 9.8 m/s²)
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Practice Questions
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Q1
A 2 kg object is dropped from a height of 5 m. What is the potential energy at the top? (g = 9.8 m/s²)
19.6 J
39.2 J
49 J
98 J
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Potential energy = mgh = 2 kg × 9.8 m/s² × 5 m = 98 J.
Questions & Step-by-step Solutions
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Q
Q: A 2 kg object is dropped from a height of 5 m. What is the potential energy at the top? (g = 9.8 m/s²)
Solution:
Potential energy = mgh = 2 kg × 9.8 m/s² × 5 m = 98 J.
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 2 kg.
Step 2: Identify the height from which the object is dropped. The height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. The value of g is 9.8 m/s².
Step 4: Use the formula for potential energy, which is PE = mgh.
Step 5: Substitute the values into the formula: PE = 2 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 2 × 9.8 × 5 = 98 J.
Step 7: Conclude that the potential energy at the top is 98 Joules.
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