If a person lifts a 50 kg box to a height of 2 meters in 5 seconds, what is the power exerted?

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Q: If a person lifts a 50 kg box to a height of 2 meters in 5 seconds, what is the power exerted?

Solution: The work done against gravity is W = mgh = (50 kg)(9.8 m/s²)(2 m) = 980 J. Power is P = W/t = 980 J / 5 s = 196 W, approximately 200 W.

Steps: 9

Step 1: Identify the mass of the box. The mass (m) is 50 kg.
Step 2: Identify the height the box is lifted. The height (h) is 2 meters.
Step 3: Identify the acceleration due to gravity. The value of gravity (g) is approximately 9.8 m/s².
Step 4: Calculate the work done (W) using the formula W = mgh. Substitute the values: W = (50 kg) * (9.8 m/s²) * (2 m).
Step 5: Perform the multiplication: W = 50 * 9.8 * 2 = 980 Joules (J).
Step 6: Identify the time taken to lift the box. The time (t) is 5 seconds.
Step 7: Calculate the power (P) using the formula P = W/t. Substitute the values: P = 980 J / 5 s.
Step 8: Perform the division: P = 980 / 5 = 196 Watts (W).
Step 9: Round the answer if necessary. The power exerted is approximately 200 W.