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A 5 kg object is lifted to a height of 10 m. What is the work done against gravi
A 5 kg object is lifted to a height of 10 m. What is the work done against gravity?
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A 5 kg object is lifted to a height of 10 m. What is the work done against gravity?
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Work done against gravity is W = mgh = 5 * 9.8 * 10 = 490 J.
Questions & Step-by-step Solutions
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Q: A 5 kg object is lifted to a height of 10 m. What is the work done against gravity?
Solution:
Work done against gravity is W = mgh = 5 * 9.8 * 10 = 490 J.
Steps: 6
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 5 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 10 m.
Step 3: Identify the acceleration due to gravity. The standard value is approximately 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is W = mgh.
Step 5: Substitute the values into the formula: W = 5 kg * 9.8 m/s² * 10 m.
Step 6: Calculate the result: W = 5 * 9.8 * 10 = 490 J.
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