Question: A pendulum swings from a height of 2 m. What is the speed at the lowest point of the swing?
Options:
Correct Answer: 4 m/s
Solution:
Using conservation of energy, potential energy at the top = kinetic energy at the bottom. mgh = 0.5mv². Solving gives v = √(2gh) = √(2 * 9.8 * 2) = 4 m/s.