A 10 kg object is lifted to a height of 2 m. What is the work done against gravi

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Question: A 10 kg object is lifted to a height of 2 m. What is the work done against gravity?

Options:

Correct Answer: 40 J

Solution:

Work done = mass × g × height = 10 kg × 9.8 m/s² × 2 m = 196 J.

A 10 kg object is lifted to a height of 2 m. What is the work done against gravity?

A 10 kg object is lifted to a height of 2 m. What is the work done against gravity?

Correct Answer: 196 J

Step 1: Identify the mass of the object. In this case, the mass is 10 kg.
Step 2: Identify the height to which the object is lifted. Here, the height is 2 m.
Step 3: Know the acceleration due to gravity (g). It is approximately 9.8 m/s².
Step 4: Use the formula for work done against gravity: Work done = mass × g × height.
Step 5: Substitute the values into the formula: Work done = 10 kg × 9.8 m/s² × 2 m.
Step 6: Calculate the result: 10 × 9.8 × 2 = 196 J.

Work Done Against Gravity – The work done against gravity is calculated using the formula: Work = mass × gravitational acceleration × height.