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A 2 kg object is dropped from a height of 5 m. What is its potential energy at t
A 2 kg object is dropped from a height of 5 m. What is its potential energy at the top?
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A 2 kg object is dropped from a height of 5 m. What is its potential energy at the top?
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Potential Energy = mass × g × height = 2 kg × 9.8 m/s² × 5 m = 98 J.
Questions & Step-by-step Solutions
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Q: A 2 kg object is dropped from a height of 5 m. What is its potential energy at the top?
Solution:
Potential Energy = mass × g × height = 2 kg × 9.8 m/s² × 5 m = 98 J.
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass is 2 kg.
Step 2: Identify the height from which the object is dropped. Here, the height is 5 m.
Step 3: Identify the acceleration due to gravity (g). The value of g is approximately 9.8 m/s².
Step 4: Use the formula for potential energy, which is: Potential Energy = mass × g × height.
Step 5: Plug in the values: Potential Energy = 2 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 2 × 9.8 × 5 = 98 J.
Step 7: Conclude that the potential energy at the top is 98 Joules.
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