A mixture contains 40% salt and 60% water. If 10 liters of water is added, what

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Question: A mixture contains 40% salt and 60% water. If 10 liters of water is added, what is the new percentage of salt in the mixture?

Options:

Correct Answer: 40%

Solution:

Initial salt = 0.4 * (10 + 10) = 4 liters. New total = 20 liters. New percentage = (4/20) * 100 = 20%.

A mixture contains 40% salt and 60% water. If 10 liters of water is added, what is the new percentage of salt in the mixture?

A mixture contains 40% salt and 60% water. If 10 liters of water is added, what is the new percentage of salt in the mixture?

Step 1: Understand that the mixture has 40% salt and 60% water.
Step 2: Assume we have 10 liters of the mixture. This means we have 4 liters of salt (40% of 10 liters) and 6 liters of water (60% of 10 liters).
Step 3: Add 10 liters of water to the mixture. Now we have 6 liters of original water + 10 liters of added water = 16 liters of water.
Step 4: The amount of salt remains the same at 4 liters since we only added water.
Step 5: Calculate the new total volume of the mixture: 4 liters of salt + 16 liters of water = 20 liters.
Step 6: Find the new percentage of salt in the mixture: (4 liters of salt / 20 liters of total mixture) * 100 = 20%.

Percentage Calculation – Understanding how to calculate the percentage of a component in a mixture after changes in volume.
Mixture Composition – Analyzing the composition of a mixture and how adding or removing components affects the overall percentages.