An object is lifted vertically 10 m against gravity. If the mass of the object i

An object is lifted vertically 10 m against gravity. If the mass of the object is 5 kg, what is the work done against gravity?

An object is lifted vertically 10 m against gravity. If the mass of the object is 5 kg, what is the work done against gravity?

Step 1: Identify the mass of the object. In this case, the mass is 5 kg.
Step 2: Identify the height the object is lifted. Here, the height is 10 m.
Step 3: Know the acceleration due to gravity (g). It is approximately 9.8 m/s².
Step 4: Use the formula for work done against gravity: Work done = mass × g × height.
Step 5: Substitute the values into the formula: Work done = 5 kg × 9.8 m/s² × 10 m.
Step 6: Calculate the result: 5 × 9.8 = 49, then 49 × 10 = 490.
Step 7: Conclude that the work done against gravity is 490 Joules (J).

Work Done Against Gravity – Work is calculated as the product of force and distance. In this case, the force is the weight of the object (mass × gravitational acceleration), and the distance is the height lifted.
Gravitational Force – Understanding that the force acting against the object is due to gravity, which is approximately 9.8 m/s² on Earth.
Units of Work – Work is measured in joules (J), where 1 J = 1 N·m (Newton meter).