A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the p

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Question: A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the potential energy stored in the spring?

Options:

Correct Answer: 1 J

Solution:

Potential Energy = 0.5 × k × x² = 0.5 × 200 N/m × (0.1 m)² = 1 J.

A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the potential energy stored in the spring?

A spring with a spring constant of 200 N/m is compressed by 0.1 m. What is the potential energy stored in the spring?

Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Identify the compression of the spring (x). Here, x = 0.1 m.
Step 3: Use the formula for potential energy stored in a spring: Potential Energy = 0.5 × k × x².
Step 4: Substitute the values into the formula: Potential Energy = 0.5 × 200 N/m × (0.1 m)².
Step 5: Calculate (0.1 m)², which is 0.01 m².
Step 6: Multiply 200 N/m by 0.01 m² to get 2 N·m.
Step 7: Multiply 2 N·m by 0.5 to find the potential energy: 0.5 × 2 N·m = 1 J.

Potential Energy in Springs – The potential energy stored in a compressed or stretched spring is calculated using the formula PE = 0.5 × k × x², where k is the spring constant and x is the displacement from the equilibrium position.