A train accelerates from rest to a speed of 72 km/h in 10 seconds. What is its a

₹0.0

Question: A train accelerates from rest to a speed of 72 km/h in 10 seconds. What is its acceleration?

Options:

Correct Answer: 2 m/s²

Solution:

Convert speed to m/s: 72 km/h = 20 m/s. Acceleration = (final speed - initial speed) / time = (20 m/s - 0) / 10 s = 2 m/s².

A train accelerates from rest to a speed of 72 km/h in 10 seconds. What is its acceleration?

A train accelerates from rest to a speed of 72 km/h in 10 seconds. What is its acceleration?

Step 1: Understand that the train starts from rest, which means its initial speed is 0 m/s.
Step 2: Convert the final speed from kilometers per hour (km/h) to meters per second (m/s).
Step 3: Use the conversion factor: 1 km/h = 1/3.6 m/s. So, 72 km/h = 72 / 3.6 = 20 m/s.
Step 4: Identify the time taken for the acceleration, which is given as 10 seconds.
Step 5: Use the formula for acceleration: Acceleration = (final speed - initial speed) / time.
Step 6: Plug in the values: Acceleration = (20 m/s - 0 m/s) / 10 s.
Step 7: Calculate the acceleration: Acceleration = 20 m/s / 10 s = 2 m/s².

Acceleration – Acceleration is the rate of change of velocity over time, calculated as the difference between final and initial speeds divided by the time taken.
Unit Conversion – Converting units from kilometers per hour to meters per second is essential for consistency in calculations.