If a wildlife reserve has 250 animals and the population increases by 10% each y

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Question: If a wildlife reserve has 250 animals and the population increases by 10% each year, how many animals will there be after 2 years?

Options:

Correct Answer: 305

Solution:

250 * (1 + 0.10)^2 = 250 * 1.21 = 302.5, rounded to 305.

If a wildlife reserve has 250 animals and the population increases by 10% each year, how many animals will there be after 2 years?

If a wildlife reserve has 250 animals and the population increases by 10% each year, how many animals will there be after 2 years?

Step 1: Start with the initial number of animals, which is 250.
Step 2: Determine the percentage increase per year, which is 10%. Convert this percentage to a decimal by dividing by 100. So, 10% becomes 0.10.
Step 3: To find the total number of animals after 2 years, we need to calculate the growth factor for 2 years. The growth factor for 1 year is (1 + 0.10) = 1.10.
Step 4: For 2 years, we raise the growth factor to the power of 2: (1.10)^2 = 1.21.
Step 5: Now, multiply the initial number of animals (250) by the growth factor (1.21): 250 * 1.21 = 302.5.
Step 6: Since we cannot have half an animal, we round 302.5 to the nearest whole number, which is 303.

Exponential Growth – Understanding how populations grow over time using a percentage increase.
Compound Interest Formula – Applying the formula for compound growth, which is similar to calculating interest.
Rounding Numbers – Knowing how to round numbers correctly in the context of population counts.