A mixture of 40 liters contains alcohol and water in the ratio 1:4. How much alc

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Question: A mixture of 40 liters contains alcohol and water in the ratio 1:4. How much alcohol is in the mixture?

Options:

Correct Answer: 8 liters

Solution:

In a 1:4 ratio, total parts = 1 + 4 = 5. Alcohol = (1/5) * 40 = 8 liters.

A mixture of 40 liters contains alcohol and water in the ratio 1:4. How much alcohol is in the mixture?

A mixture of 40 liters contains alcohol and water in the ratio 1:4. How much alcohol is in the mixture?

Step 1: Understand the ratio of alcohol to water, which is 1:4.
Step 2: Add the parts of the ratio together: 1 (for alcohol) + 4 (for water) = 5 total parts.
Step 3: Determine how much one part is worth by dividing the total volume (40 liters) by the total parts (5): 40 liters / 5 parts = 8 liters per part.
Step 4: Since alcohol is 1 part, multiply the value of one part (8 liters) by the number of parts for alcohol (1): 1 * 8 liters = 8 liters of alcohol.

Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
Basic Arithmetic – Performing multiplication and division to find parts of a whole.