A mixture of two alloys A and B is in the ratio 5:2. If the total weight of the

₹0.0

Question: A mixture of two alloys A and B is in the ratio 5:2. If the total weight of the mixture is 70 kg, how much of alloy B is there?

Options:

Correct Answer: 20 kg

Solution:

Total parts = 5 + 2 = 7. Alloy B = (2/7) * 70 = 20 kg.

A mixture of two alloys A and B is in the ratio 5:2. If the total weight of the mixture is 70 kg, how much of alloy B is there?

A mixture of two alloys A and B is in the ratio 5:2. If the total weight of the mixture is 70 kg, how much of alloy B is there?

Step 1: Understand the ratio of the alloys A and B, which is 5:2.
Step 2: Add the parts of the ratio together: 5 (for A) + 2 (for B) = 7 parts total.
Step 3: Find out how much one part weighs by dividing the total weight of the mixture (70 kg) by the total parts (7): 70 kg / 7 = 10 kg per part.
Step 4: Determine how many parts of alloy B there are, which is 2 parts.
Step 5: Calculate the weight of alloy B by multiplying the weight of one part (10 kg) by the number of parts for B (2): 10 kg * 2 = 20 kg.

Ratio and Proportion – Understanding how to divide a total quantity based on given ratios.
Weight Calculation – Calculating the weight of a component in a mixture based on its proportion.