A solution contains alcohol and water in the ratio 5:3. If the total volume of t

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Question: A solution contains alcohol and water in the ratio 5:3. If the total volume of the solution is 64 liters, how much water is present?

Options:

Correct Answer: 24 liters

Solution:

Total parts = 5 + 3 = 8. Water = (3/8) * 64 = 24 liters.

A solution contains alcohol and water in the ratio 5:3. If the total volume of the solution is 64 liters, how much water is present?

A solution contains alcohol and water in the ratio 5:3. If the total volume of the solution is 64 liters, how much water is present?

Step 1: Understand the ratio of alcohol to water, which is 5:3.
Step 2: Add the parts of the ratio together: 5 (alcohol) + 3 (water) = 8 parts total.
Step 3: Determine how much one part is worth by dividing the total volume of the solution (64 liters) by the total parts (8): 64 / 8 = 8 liters per part.
Step 4: Find out how many parts of water there are, which is 3 parts.
Step 5: Calculate the volume of water by multiplying the number of parts of water (3) by the volume of one part (8 liters): 3 * 8 = 24 liters.
Step 6: Conclude that there are 24 liters of water in the solution.

Ratio and Proportion – Understanding how to divide a total quantity based on given ratios.
Basic Arithmetic – Performing addition and multiplication to find parts of a whole.