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If 500 J of heat is added to a system and 200 J of work is done by the system, w

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Question: If 500 J of heat is added to a system and 200 J of work is done by the system, what is the change in internal energy?

Options:

  1. 300 J
  2. 500 J
  3. 700 J
  4. 200 J

Correct Answer: 300 J

Solution: 

According to the first law of thermodynamics, ΔU = Q - W. Here, ΔU = 500 J - 200 J = 300 J.

If 500 J of heat is added to a system and 200 J of work is done by the system, w

Practice Questions

Q1
If 500 J of heat is added to a system and 200 J of work is done by the system, what is the change in internal energy?
  1. 300 J
  2. 500 J
  3. 700 J
  4. 200 J

Questions & Step-by-Step Solutions

If 500 J of heat is added to a system and 200 J of work is done by the system, what is the change in internal energy?
Correct Answer: 300 J
  • Step 1: Identify the amount of heat added to the system, which is 500 J. This is represented as Q.
  • Step 2: Identify the amount of work done by the system, which is 200 J. This is represented as W.
  • Step 3: Use the formula from the first law of thermodynamics, which is ΔU = Q - W.
  • Step 4: Substitute the values into the formula: ΔU = 500 J - 200 J.
  • Step 5: Calculate the result: ΔU = 300 J.
  • First Law of Thermodynamics – The principle that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W).
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