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What is the moment of inertia of a thin circular ring of mass M and radius R abo

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Question: What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane and passing through its center?

Options:

  1. MR^2
  2. 1/2 MR^2
  3. 1/3 MR^2
  4. 2/5 MR^2

Correct Answer: MR^2

Solution: 

The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.

What is the moment of inertia of a thin circular ring of mass M and radius R abo

Practice Questions

Q1
What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane and passing through its center?
  1. MR^2
  2. 1/2 MR^2
  3. 1/3 MR^2
  4. 2/5 MR^2

Questions & Step-by-Step Solutions

What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane and passing through its center?
Correct Answer: I = MR^2
  • Step 1: Understand what moment of inertia means. It is a measure of how difficult it is to change the rotation of an object.
  • Step 2: Identify the shape of the object. In this case, it is a thin circular ring.
  • Step 3: Recognize the parameters given: the mass (M) of the ring and the radius (R) of the ring.
  • Step 4: Recall the formula for the moment of inertia of a thin circular ring about an axis through its center. The formula is I = MR^2.
  • Step 5: Substitute the values of mass (M) and radius (R) into the formula if needed, but the formula itself is already in terms of M and R.
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