What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane and passing through its center?
Practice Questions
1 question
Q1
What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane and passing through its center?
MR^2
1/2 MR^2
1/3 MR^2
2/5 MR^2
The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Questions & Step-by-step Solutions
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Q
Q: What is the moment of inertia of a thin circular ring of mass M and radius R about an axis perpendicular to its plane and passing through its center?
Solution: The moment of inertia of a thin circular ring about an axis through its center is I = MR^2.
Steps: 5
Step 1: Understand what moment of inertia means. It is a measure of how difficult it is to change the rotation of an object.
Step 2: Identify the shape of the object. In this case, it is a thin circular ring.
Step 3: Recognize the parameters given: the mass (M) of the ring and the radius (R) of the ring.
Step 4: Recall the formula for the moment of inertia of a thin circular ring about an axis through its center. The formula is I = MR^2.
Step 5: Substitute the values of mass (M) and radius (R) into the formula if needed, but the formula itself is already in terms of M and R.
