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A particle is moving in a straight line with a velocity v. If it suddenly starts

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Question: A particle is moving in a straight line with a velocity v. If it suddenly starts moving in a circular path of radius r, what will be its angular momentum about the center of the circular path?

Options:

  1. 0
  2. mv
  3. mvr
  4. mv^2/r

Correct Answer: mvr

Solution: 

Angular momentum L = mvr, where v is the linear speed and r is the radius of the circular path.

A particle is moving in a straight line with a velocity v. If it suddenly starts

Practice Questions

Q1
A particle is moving in a straight line with a velocity v. If it suddenly starts moving in a circular path of radius r, what will be its angular momentum about the center of the circular path?
  1. 0
  2. mv
  3. mvr
  4. mv^2/r

Questions & Step-by-Step Solutions

A particle is moving in a straight line with a velocity v. If it suddenly starts moving in a circular path of radius r, what will be its angular momentum about the center of the circular path?
Correct Answer: mvr
  • Step 1: Understand that angular momentum is a measure of how much motion an object has when it moves in a circular path.
  • Step 2: Identify the variables: 'm' is the mass of the particle, 'v' is the linear velocity (speed in a straight line), and 'r' is the radius of the circular path.
  • Step 3: Recall the formula for angular momentum (L) in circular motion: L = mvr.
  • Step 4: Plug in the values of mass (m), velocity (v), and radius (r) into the formula to calculate the angular momentum.
  • Step 5: The result will give you the angular momentum of the particle about the center of the circular path.
  • Angular Momentum – Angular momentum is the product of the linear momentum and the radius from the axis of rotation, given by the formula L = mvr.
  • Circular Motion – When a particle moves in a circular path, its linear velocity is related to its angular velocity and the radius of the circle.
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