Question: A mixture contains sugar and water in the ratio 3:5. If there are 40 grams of the mixture, how much sugar is there?
Options:
15 grams
20 grams
12 grams
18 grams
Correct Answer: 15 grams
Solution:
In a 3:5 ratio, total parts = 3 + 5 = 8. Sugar = (3/8) * 40 = 15 grams.
A mixture contains sugar and water in the ratio 3:5. If there are 40 grams of th
Practice Questions
Q1
A mixture contains sugar and water in the ratio 3:5. If there are 40 grams of the mixture, how much sugar is there?
15 grams
20 grams
12 grams
18 grams
Questions & Step-by-Step Solutions
A mixture contains sugar and water in the ratio 3:5. If there are 40 grams of the mixture, how much sugar is there?
Step 1: Understand the ratio of sugar to water, which is 3:5.
Step 2: Add the parts of the ratio together: 3 (sugar) + 5 (water) = 8 parts total.
Step 3: Find out how much one part is worth by dividing the total mixture weight by the total parts: 40 grams / 8 parts = 5 grams per part.
Step 4: Calculate the amount of sugar by multiplying the number of sugar parts by the weight of one part: 3 parts (sugar) * 5 grams per part = 15 grams of sugar.
Ratio and Proportion – Understanding how to divide a total quantity based on given ratios.
Basic Arithmetic – Performing multiplication and division to find specific quantities from a total.
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