Question: A mixture of 40 liters contains 10% salt. If 5 liters of the mixture is removed and replaced with water, what is the new percentage of salt?
Options:
Correct Answer: 8%
Solution:
Initial salt = 10% of 40L = 4L. After removing 5L, salt left = 4L - (10% of 5L) = 4L - 0.5L = 3.5L. New volume = 40L. New percentage = (3.5/40) * 100 = 8%.