A mixture consists of sugar and water in the ratio 1:5. If the total weight of t

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Question: A mixture consists of sugar and water in the ratio 1:5. If the total weight of the mixture is 60 grams, how much sugar is there?

Options:

Correct Answer: 10 grams

Solution:

In a 1:5 ratio, the total parts = 1 + 5 = 6. Sugar = (1/6) * 60 = 10 grams.

A mixture consists of sugar and water in the ratio 1:5. If the total weight of the mixture is 60 grams, how much sugar is there?

A mixture consists of sugar and water in the ratio 1:5. If the total weight of the mixture is 60 grams, how much sugar is there?

Step 1: Understand the ratio of sugar to water, which is 1:5.
Step 2: Add the parts of the ratio together: 1 (sugar) + 5 (water) = 6 parts total.
Step 3: Find out how much one part is worth by dividing the total weight of the mixture (60 grams) by the total parts (6): 60 grams / 6 parts = 10 grams per part.
Step 4: Since sugar is 1 part, multiply the value of one part (10 grams) by the number of parts for sugar (1): 1 * 10 grams = 10 grams of sugar.

Ratio and Proportion – Understanding how to divide a total quantity based on given ratios.
Basic Arithmetic – Performing calculations involving addition, multiplication, and division.