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If 30 liters of a mixture contains alcohol and water in the ratio 2:3, how much

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Question: If 30 liters of a mixture contains alcohol and water in the ratio 2:3, how much alcohol is in the mixture?

Options:

  1. 12 liters
  2. 18 liters
  3. 15 liters
  4. 10 liters

Correct Answer: 12 liters

Solution: 

In a 2:3 ratio, the total parts = 2 + 3 = 5. Alcohol = (2/5) * 30 = 12 liters.

If 30 liters of a mixture contains alcohol and water in the ratio 2:3, how much

Practice Questions

Q1
If 30 liters of a mixture contains alcohol and water in the ratio 2:3, how much alcohol is in the mixture?
  1. 12 liters
  2. 18 liters
  3. 15 liters
  4. 10 liters

Questions & Step-by-Step Solutions

If 30 liters of a mixture contains alcohol and water in the ratio 2:3, how much alcohol is in the mixture?
  • Step 1: Understand the ratio of alcohol to water, which is 2:3.
  • Step 2: Add the parts of the ratio together: 2 (for alcohol) + 3 (for water) = 5 total parts.
  • Step 3: Find the fraction of the mixture that is alcohol by dividing the alcohol part by the total parts: 2/5.
  • Step 4: Multiply the total volume of the mixture (30 liters) by the fraction of alcohol: (2/5) * 30.
  • Step 5: Calculate the amount of alcohol: 2/5 of 30 liters equals 12 liters.
  • Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
  • Mixture Problems – Calculating the components of a mixture based on their ratios.
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