What is the fundamental frequency of a pipe open at both ends if its length is 2

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Question: What is the fundamental frequency of a pipe open at both ends if its length is 2 m?

Options:

Correct Answer: 170 Hz

Solution:

The fundamental frequency is given by f = v/λ. For a pipe open at both ends, λ = 2L = 4 m. Thus, f = 343 m/s / 4 m = 85.75 Hz, approximately 85 Hz.

What is the fundamental frequency of a pipe open at both ends if its length is 2 m?

What is the fundamental frequency of a pipe open at both ends if its length is 2 m?

Correct Answer: 85 Hz

Step 1: Identify the length of the pipe. In this case, the length (L) is 2 meters.
Step 2: Understand that for a pipe open at both ends, the wavelength (λ) of the fundamental frequency is twice the length of the pipe. So, λ = 2L = 2 * 2 m = 4 m.
Step 3: Use the formula for frequency, which is f = v/λ, where v is the speed of sound in air (approximately 343 m/s).
Step 4: Substitute the values into the formula: f = 343 m/s / 4 m.
Step 5: Calculate the frequency: f = 85.75 Hz.
Step 6: Round the answer to the nearest whole number, which is approximately 85 Hz.

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