A simple harmonic oscillator has a total energy of 50 J and an amplitude of 10 c

Practice Questions

Q1
A simple harmonic oscillator has a total energy of 50 J and an amplitude of 10 cm. What is the spring constant?
  1. 200 N/m
  2. 500 N/m
  3. 1000 N/m
  4. 2000 N/m

Questions & Step-by-Step Solutions

A simple harmonic oscillator has a total energy of 50 J and an amplitude of 10 cm. What is the spring constant?
Correct Answer: 500 N/m
  • Step 1: Understand that the total energy (E) of a simple harmonic oscillator is given by the formula E = (1/2)kA^2, where k is the spring constant and A is the amplitude.
  • Step 2: Identify the values given in the problem. The total energy E is 50 J and the amplitude A is 10 cm. Convert the amplitude from cm to meters: 10 cm = 0.1 m.
  • Step 3: Substitute the known values into the formula: 50 = (1/2)k(0.1^2).
  • Step 4: Calculate (0.1^2), which is 0.01.
  • Step 5: Rewrite the equation with the calculated value: 50 = (1/2)k(0.01).
  • Step 6: Multiply both sides of the equation by 2 to eliminate the fraction: 100 = k(0.01).
  • Step 7: Divide both sides by 0.01 to solve for k: k = 100 / 0.01.
  • Step 8: Calculate the value of k: k = 10000 N/m.
  • Simple Harmonic Motion – The behavior of oscillating systems where the restoring force is proportional to the displacement from equilibrium.
  • Energy in Simple Harmonic Oscillator – The total mechanical energy in a simple harmonic oscillator is constant and is given by the formula E = (1/2)kA^2, where k is the spring constant and A is the amplitude.
  • Spring Constant – A measure of the stiffness of a spring, defined as the force required to compress or extend the spring by a unit distance.
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