A mixture contains two liquids in the ratio 3:5. If the total volume of the mixt

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Question: A mixture contains two liquids in the ratio 3:5. If the total volume of the mixture is 80 liters, how much of the first liquid is there?

Options:

30 liters
40 liters
50 liters
20 liters

Correct Answer: 40 liters

Solution:

Total parts = 3 + 5 = 8. First liquid = (3/8) * 80 = 30 liters.

A mixture contains two liquids in the ratio 3:5. If the total volume of the mixt

Practice Questions

A mixture contains two liquids in the ratio 3:5. If the total volume of the mixture is 80 liters, how much of the first liquid is there?

30 liters
40 liters
50 liters
20 liters

Questions & Step-by-Step Solutions

A mixture contains two liquids in the ratio 3:5. If the total volume of the mixture is 80 liters, how much of the first liquid is there?

Step 1: Understand the ratio of the two liquids, which is 3:5.
Step 2: Add the parts of the ratio together: 3 + 5 = 8 parts total.
Step 3: Find out how much one part is worth by dividing the total volume by the total parts: 80 liters / 8 parts = 10 liters per part.
Step 4: Calculate the amount of the first liquid by multiplying its part (3) by the value of one part: 3 parts * 10 liters/part = 30 liters.

Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
Basic Arithmetic – Performing calculations involving addition, multiplication, and division.

A mixture contains two liquids in the ratio 3:5. If the total volume of the mixt

What’s inside this PDF?

A mixture contains two liquids in the ratio 3:5. If the total volume of the mixt

Practice Questions

Questions & Step-by-Step Solutions

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