A mixture of two chemicals X and Y is in the ratio 7:2. If there are 81 liters o

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Question: A mixture of two chemicals X and Y is in the ratio 7:2. If there are 81 liters of the mixture, how much of chemical Y is there?

Options:

Correct Answer: 18 liters

Solution:

Total parts = 7 + 2 = 9. Y = (2/9) * 81 = 18 liters.

A mixture of two chemicals X and Y is in the ratio 7:2. If there are 81 liters of the mixture, how much of chemical Y is there?

A mixture of two chemicals X and Y is in the ratio 7:2. If there are 81 liters of the mixture, how much of chemical Y is there?

Step 1: Understand the ratio of chemicals X and Y, which is 7:2.
Step 2: Add the parts of the ratio together: 7 (for X) + 2 (for Y) = 9 parts total.
Step 3: Find out how much one part is worth by dividing the total mixture (81 liters) by the total parts (9): 81 liters ÷ 9 parts = 9 liters per part.
Step 4: Since Y has 2 parts, multiply the value of one part (9 liters) by 2: 9 liters × 2 = 18 liters.
Step 5: Conclude that there are 18 liters of chemical Y in the mixture.

Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
Basic Arithmetic – Performing calculations involving addition, multiplication, and division.