If 15 liters of a solution contains alcohol and water in the ratio 1:4, how much

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Question: If 15 liters of a solution contains alcohol and water in the ratio 1:4, how much alcohol is present?

Options:

Correct Answer: 3 liters

Solution:

Total parts = 1 + 4 = 5. Alcohol = (1/5) * 15 = 3 liters.

If 15 liters of a solution contains alcohol and water in the ratio 1:4, how much alcohol is present?

If 15 liters of a solution contains alcohol and water in the ratio 1:4, how much alcohol is present?

Step 1: Understand the ratio of alcohol to water, which is 1:4.
Step 2: Add the parts of the ratio together: 1 (alcohol) + 4 (water) = 5 parts total.
Step 3: Find out how much one part is by dividing the total volume of the solution (15 liters) by the total parts (5): 15 liters / 5 parts = 3 liters per part.
Step 4: Since alcohol is 1 part, multiply the amount of one part (3 liters) by the number of parts for alcohol (1): 1 part * 3 liters/part = 3 liters of alcohol.

Ratio and Proportion – Understanding how to divide a total quantity based on given ratios.
Basic Arithmetic – Performing multiplication and division to find parts of a whole.