Question: If the angle of elevation from a point 50 meters away from the base of a tower is 30 degrees, what is the height of the tower?
Options:
Correct Answer: 25 meters
Solution:
Let h be the height of the tower. tan(30°) = h/50. Therefore, h = 50 * tan(30°) = 50 * (1/√3) = 50/√3 = 25√3/3 meters.