A simple harmonic oscillator has a mass of 2 kg and a spring constant of 50 N/m.

Practice Questions

Q1
A simple harmonic oscillator has a mass of 2 kg and a spring constant of 50 N/m. What is the angular frequency of the oscillator?
  1. 5 rad/s
  2. 10 rad/s
  3. 15 rad/s
  4. 20 rad/s

Questions & Step-by-Step Solutions

A simple harmonic oscillator has a mass of 2 kg and a spring constant of 50 N/m. What is the angular frequency of the oscillator?
  • Step 1: Identify the mass (m) of the oscillator, which is given as 2 kg.
  • Step 2: Identify the spring constant (k) of the oscillator, which is given as 50 N/m.
  • Step 3: Write down the formula for angular frequency (ω), which is ω = √(k/m).
  • Step 4: Substitute the values of k and m into the formula: ω = √(50/2).
  • Step 5: Calculate the value inside the square root: 50 divided by 2 equals 25.
  • Step 6: Take the square root of 25, which equals 5.
  • Step 7: Conclude that the angular frequency (ω) is 5 rad/s.
  • Simple Harmonic Motion – The study of oscillatory motion where the restoring force is proportional to the displacement from equilibrium.
  • Angular Frequency – A measure of how quickly an object oscillates, calculated using the formula ω = √(k/m).
  • Spring Constant – A measure of the stiffness of a spring, represented by k in Hooke's law.
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