A and B are mixed in the ratio 1:3. If there are 48 liters of the mixture, how m

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Question: A and B are mixed in the ratio 1:3. If there are 48 liters of the mixture, how much of liquid A is there?

Options:

Correct Answer: 16 liters

Solution:

In a 1:3 ratio, the total parts = 1 + 3 = 4. Liquid A = (1/4) * 48 = 12 liters.

A and B are mixed in the ratio 1:3. If there are 48 liters of the mixture, how much of liquid A is there?

A and B are mixed in the ratio 1:3. If there are 48 liters of the mixture, how much of liquid A is there?

Step 1: Understand the ratio of A to B, which is 1:3. This means for every 1 part of A, there are 3 parts of B.
Step 2: Add the parts of A and B together to find the total parts. 1 part (A) + 3 parts (B) = 4 total parts.
Step 3: Determine how much one part is worth by dividing the total volume of the mixture by the total parts. 48 liters ÷ 4 parts = 12 liters per part.
Step 4: Since A is 1 part, multiply the value of one part by the number of parts for A. 1 part × 12 liters/part = 12 liters of A.

Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
Mixture Problems – Applying ratios to find the quantity of individual components in a mixture.